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X^2+.5X-19.25=0
a = 1; b = .5; c = -19.25;
Δ = b2-4ac
Δ = .52-4·1·(-19.25)
Δ = 77.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.5)-\sqrt{77.25}}{2*1}=\frac{-0.5-\sqrt{77.25}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.5)+\sqrt{77.25}}{2*1}=\frac{-0.5+\sqrt{77.25}}{2} $
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